Transpose of a given matrix using pointer - C

Q. Write a program using pointer, to find transpose of a given matrix.
#BIT_2017_2b_5Marks_Solution
==> code goes like this:

#include<stdio.h>
int main()
{
int a[10][10],b[10][10];
int i,j,rows,cols;
printf("Enter size of matrix: ");
scanf("%d %d",&rows,&cols);
//For Input
printf("Enter elements :");
for(i=0;i<rows;i++)
{
    for ( j = 0; j < cols; j++)
    {
        scanf("%d",(*(a+i)+j));
    }
}
//For Transpose
for ( i = 0; i < rows; i++)
{
    for ( j = 0; j < cols; j++)
    {
        *(*(b+j)+i)=*(*(a+i)+j);
        printf("%d \t",*(*(b+i)+j));
    }
}
//For Displaying Transpose
for ( i = 0; i < rows; i++)
{
    for ( j = 0; j < cols; j++)
    {
        printf("%d \t",*(*(b+i)+j));
    }
    printf("\n");
}
return 0;
}

Output:

If you are using Turbo C++ IDE, then use conio.h in link section after stdio.h
and use getch(); to hold the output screen, just before the end of main function.
If you have any confusion regarding the program, please, comment below.
Happy Coding !
Thank you 

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