Q. Write a program to multiply given two matrix of given order.
#BIT-C Programming-2019-GroupB-5No-8 Marks-Solution
==> Code goes like this:
#include<stdio.h>
int main()
{
int row1, col1, row2, col2, i, j, k, sum = 0;
int first[10][10], second[10][10], multiply[10][10];
printf("Enter number of rows and columns of first matrix:\n");
scanf("%d%d", &row1, &col1);
printf("Enter elements of first matrix:\n");
for (i = 0; i < row1; i++)
for (j = 0; j < col1; j++)
scanf("%d", &first[i][j]);
printf("Enter number of rows and columns of second matrix:\n");
scanf("%d%d", &row2, &col2);
if (col1 != row2)
printf("The multiplication isn't possible.\n");
else
{
printf("Enter elements of second matrix:\n");
for (i = 0; i < row2; i++)
for (j = 0; j < col2; j++)
scanf("%d", &second[i][j]);
for (i = 0; i < row1; i++) {
for (j = 0; j < col2; j++) {
for (k = 0; k < row2; k++) {
sum = sum + first[i][k]*second[k][j];
}
multiply[i][j] = sum;
sum = 0;
}
}
printf("Product of the matrices:\n");
for (i = 0; i < row1; i++) {
for (j = 0; j < col2; j++)
printf("%d\t", multiply[i][j]);
printf("\n");
}
}
return 0;
}
Output:
If you are using Turbo C++ IDE, then use conio.h in link section after stdio.h
and use getch(); to hold the output screen, just before the end of main function.
If you have any confusion regarding the program, please, comment below.
Happy Coding !
Thank you
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